C(n,0)-C(n,1)+C(n,2)+or-...C(n,n)=0
also written as:
the sum of i=0 to n and (-1)^i*[C(n,i)]=0
since i need to prove it with a negative, im having a really,really difficult time.
i can do one without a negative:
example:sum of i=0 to n and C(n,i)=2^n, this doesnt have a negative.In the problem where it states the sum, i mean to put the summation sign if that confuses you at all.nobody else has been able to really help me out, if you can help me out at all with this one it will be greattttly appreciated, thankyou :)
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